A stallholder started the day with 470 kiwis. He sold
310 of the kiwis and gave
17 of the remainder away. He placed the rest into boxes of 47. How many boxes would he need?
Sold |
Remainder |
Total |
3 u |
7 u |
10 u |
|
Gave away |
Rest |
|
3 u |
1 u |
6 u |
10 u |
Total number of kiwis = 10 u
10 u = 470
1 u = 470 ÷ 10 = 47
Number of kiwis that were left
= 6 u
= 6 x 47
= 282
Number of boxes that the stallholder would need
= 282 ÷ 47
= 6
Answer(s): 6