A store owner started the day with 720 chikoos. He sold
310 of the chikoos and gave
37 of the remainder away. He placed the rest into containers of 36. How many containers would he need?
Sold |
Remainder |
Total |
3 u |
7 u |
10 u |
|
Gave away |
Rest |
|
3 u |
3 u |
4 u |
10 u |
Total number of chikoos = 10 u
10 u = 720
1 u = 720 ÷ 10 = 72
Number of chikoos that were left
= 4 u
= 4 x 72
= 288
Number of containers that the store owner would need
= 288 ÷ 36
= 8
Answer(s): 8