At a gathering,
57 of the people who attended were adults.
34 of the remainder were boys and the rest were girls. If there were 117 more adults than girls, how many children attended the gathering?
| Adults |
Children |
5x2 =
10 u |
2x2 =
4 u |
| |
Boys |
Girls |
| |
4x1 =
4 u |
| |
3x1 =
3 u |
1x1 =
1 u |
| 10 u |
3 u |
1 u |
The number of children is the combined repeated identity. Make the number of children the same. LCM of 2 and 4 is 4.
Number of more adults than girls
= 10 u - 1 u
= 9 u
9 u = 117
1 u = 117 ÷ 9 = 13
Number of children who attended the gathering
= 4 u
= 4 x 13
= 52
Answer(s): 52
