Mrs Xavier baked some tarts. She gave
47 of the tarts to her father and
49 of the remainder to her cousin. Given that she gave 40 less tarts to her cousin than her father. How many tarts did
she bake at first?
Father |
Remainder |
Total |
4x3 |
3x3 |
7x3 |
|
Cousin |
Left |
|
12 u |
4 u |
5 u |
21 u |
Number of less tarts that Mrs Xavier gave to her cousin than her father
= 12 u - 4 u
= 8 u
8 u = 40
1 u = 40 ÷ 8 = 5
Number of tarts that Mrs Xavier baked at first
= 21 u
= 21 x 5
= 105
Answer(s): 105