Abi used
45 of the wire to tie some presents. She threw away
37 of the remaining wire. As a result, she had 48 cm of the wire left. How much wire did Abi have at first? Give your answer in cm.
Fraction of the wire left after tying some presents
= 1 -
45=
15 Fraction of the remaining wire left after throwing away
= 1 -
37=
47
Fraction of the total wire left
=
15 ×
47=
435
Length of the wire at first = 35 u
Length of the wire left = 4 u
4 u = 48
1 u = 48 ÷ 4 = 12
Length of the wire at first
= 35 u
= 35 x 12
= 420 cm
Answer(s): 420 cm