Vincent and Wesley gave away the same number of coins. Vincent gave away
35 of his coins while Wesley gave
59 of his coins away. Given that Vincent had 10 coins less than Wesley at first, how many coins did Vincent have at first?
| |
Vincent |
Wesley |
| Before |
5x5 =
25 u |
9x3 =
27 u |
| Change |
- 3x5 =
- 15 u |
- 5x3 =
- 15 u |
| After |
2x5 =
10 u |
4x3 =
12 u |
The number of coins that Vincent and Wesley gave away is the same. Make the number of coins that Vincent and Wesley gave away the same. LCM of 3 and 5 is 15.
Number of coins that Vincent had at first = 25 u
Number of coins that Wesley had at first = 27 u
Number of coins that Vincent had less than Wesley at first
= 27 u - 25 u
= 2 u
2 u = 10
1 u = 10 ÷ 2 = 5
Number of coins that Vincent had at first
= 25 u
= 25 x 5
= 125
Answer(s): 125
