Fred and Jeremy gave away the same number of buttons. Fred gave away
35 of his buttons while Jeremy gave
59 of his buttons away. Given that Fred had 18 buttons less than Jeremy at first, how many buttons did Fred have at first?
|
Fred |
Jeremy |
Before |
5x5 = 25 u |
9x3 = 27 u |
Change |
- 3x5 = - 15 u |
- 5x3 = - 15 u |
After |
2x5 = 10 u |
4x3 = 12 u |
The number of buttons that Fred and Jeremy gave away is the same. Make the number of buttons that Fred and Jeremy gave away the same. LCM of 3 and 5 is 15.
Number of buttons that Fred had at first = 25 u
Number of buttons that Jeremy had at first = 27 u
Number of buttons that Fred had less than Jeremy at first
= 27 u - 25 u
= 2 u
2 u = 18
1 u = 18 ÷ 2 = 9
Number of buttons that Fred had at first
= 25 u
= 25 x 9
= 225
Answer(s): 225