Tim and Eric gave away the same number of stickers. Tim gave away
34 of his stickers while Eric gave
59 of his stickers away. Given that Tim had 14 stickers less than Eric at first, how many stickers did Tim have at first?
| |
Tim |
Eric |
| Before |
4x5 =
20 u |
9x3 =
27 u |
| Change |
- 3x5 =
- 15 u |
- 5x3 =
- 15 u |
| After |
1x5 =
5 u |
4x3 =
12 u |
The number of stickers that Tim and Eric gave away is the same. Make the number of stickers that Tim and Eric gave away the same. LCM of 3 and 5 is 15.
Number of stickers that Tim had at first = 20 u
Number of stickers that Eric had at first = 27 u
Number of stickers that Tim had less than Eric at first
= 27 u - 20 u
= 7 u
7 u = 14
1 u = 14 ÷ 7 = 2
Number of stickers that Tim had at first
= 20 u
= 20 x 2
= 40
Answer(s): 40
