Gabriel and Tommy gave away the same number of pens. Gabriel gave away
35 of his pens while Tommy gave
49 of his pens away. Given that Gabriel had 21 pens less than Tommy at first, how many pens did Gabriel have at first?
| |
Gabriel |
Tommy |
| Before |
5x4 =
20 u |
9x3 =
27 u |
| Change |
- 3x4 =
- 12 u |
- 4x3 =
- 12 u |
| After |
2x4 =
8 u |
5x3 =
15 u |
The number of pens that Gabriel and Tommy gave away is the same. Make the number of pens that Gabriel and Tommy gave away the same. LCM of 3 and 4 is 12.
Number of pens that Gabriel had at first = 20 u
Number of pens that Tommy had at first = 27 u
Number of pens that Gabriel had less than Tommy at first
= 27 u - 20 u
= 7 u
7 u = 21
1 u = 21 ÷ 7 = 3
Number of pens that Gabriel had at first
= 20 u
= 20 x 3
= 60
Answer(s): 60
