Michael and Sam gave away the same number of stickers. Michael gave away
611 of his stickers while Sam gave
49 of his stickers away. Given that Michael had 10 stickers less than Sam at first, how many stickers did Michael have at first?
|
Michael |
Sam |
Before |
11x2 = 22 u |
9x3 = 27 u |
Change |
- 6x2 = - 12 u |
- 4x3 = - 12 u |
After |
5x2 = 10 u |
5x3 = 15 u |
The number of stickers that Michael and Sam gave away is the same. Make the number of stickers that Michael and Sam gave away the same. LCM of 6 and 4 is 12.
Number of stickers that Michael had at first = 22 u
Number of stickers that Sam had at first = 27 u
Number of stickers that Michael had less than Sam at first
= 27 u - 22 u
= 5 u
5 u = 10
1 u = 10 ÷ 5 = 2
Number of stickers that Michael had at first
= 22 u
= 22 x 2
= 44
Answer(s): 44