Cole and Luis gave away the same number of marbles. Cole gave away
611 of his marbles while Luis gave
49 of his marbles away. Given that Cole had 20 marbles less than Luis at first, how many marbles did Cole have at first?
|
Cole |
Luis |
Before |
11x2 = 22 u |
9x3 = 27 u |
Change |
- 6x2 = - 12 u |
- 4x3 = - 12 u |
After |
5x2 = 10 u |
5x3 = 15 u |
The number of marbles that Cole and Luis gave away is the same. Make the number of marbles that Cole and Luis gave away the same. LCM of 6 and 4 is 12.
Number of marbles that Cole had at first = 22 u
Number of marbles that Luis had at first = 27 u
Number of marbles that Cole had less than Luis at first
= 27 u - 22 u
= 5 u
5 u = 20
1 u = 20 ÷ 5 = 4
Number of marbles that Cole had at first
= 22 u
= 22 x 4
= 88
Answer(s): 88