Michael and Carl gave away the same number of beads. Michael gave away
611 of his beads while Carl gave
49 of his beads away. Given that Michael had 20 beads less than Carl at first, how many beads did Michael have at first?
| |
Michael |
Carl |
| Before |
11x2 =
22 u |
9x3 =
27 u |
| Change |
- 6x2 =
- 12 u |
- 4x3 =
- 12 u |
| After |
5x2 =
10 u |
5x3 =
15 u |
The number of beads that Michael and Carl gave away is the same. Make the number of beads that Michael and Carl gave away the same. LCM of 6 and 4 is 12.
Number of beads that Michael had at first = 22 u
Number of beads that Carl had at first = 27 u
Number of beads that Michael had less than Carl at first
= 27 u - 22 u
= 5 u
5 u = 20
1 u = 20 ÷ 5 = 4
Number of beads that Michael had at first
= 22 u
= 22 x 4
= 88
Answer(s): 88
