Sean and Howard gave away the same number of pens. Sean gave away
611 of his pens while Howard gave
49 of his pens away. Given that Sean had 25 pens less than Howard at first, how many pens did Sean have at first?
| |
Sean |
Howard |
| Before |
11x2 =
22 u |
9x3 =
27 u |
| Change |
- 6x2 =
- 12 u |
- 4x3 =
- 12 u |
| After |
5x2 =
10 u |
5x3 =
15 u |
The number of pens that Sean and Howard gave away is the same. Make the number of pens that Sean and Howard gave away the same. LCM of 6 and 4 is 12.
Number of pens that Sean had at first = 22 u
Number of pens that Howard had at first = 27 u
Number of pens that Sean had less than Howard at first
= 27 u - 22 u
= 5 u
5 u = 25
1 u = 25 ÷ 5 = 5
Number of pens that Sean had at first
= 22 u
= 22 x 5
= 110
Answer(s): 110
