Ken and Daniel gave away the same number of pens. Ken gave away
35 of his pens while Daniel gave
59 of his pens away. Given that Ken had 18 pens less than Daniel at first, how many pens did Ken have at first?
|
Ken |
Daniel |
Before |
5x5 = 25 u |
9x3 = 27 u |
Change |
- 3x5 = - 15 u |
- 5x3 = - 15 u |
After |
2x5 = 10 u |
4x3 = 12 u |
The number of pens that Ken and Daniel gave away is the same. Make the number of pens that Ken and Daniel gave away the same. LCM of 3 and 5 is 15.
Number of pens that Ken had at first = 25 u
Number of pens that Daniel had at first = 27 u
Number of pens that Ken had less than Daniel at first
= 27 u - 25 u
= 2 u
2 u = 18
1 u = 18 ÷ 2 = 9
Number of pens that Ken had at first
= 25 u
= 25 x 9
= 225
Answer(s): 225