Henry and Fabian gave away the same number of beads. Henry gave away
35 of his beads while Fabian gave
59 of his beads away. Given that Henry had 22 beads less than Fabian at first, how many beads did Henry have at first?
| |
Henry |
Fabian |
| Before |
5x5 =
25 u |
9x3 =
27 u |
| Change |
- 3x5 =
- 15 u |
- 5x3 =
- 15 u |
| After |
2x5 =
10 u |
4x3 =
12 u |
The number of beads that Henry and Fabian gave away is the same. Make the number of beads that Henry and Fabian gave away the same. LCM of 3 and 5 is 15.
Number of beads that Henry had at first = 25 u
Number of beads that Fabian had at first = 27 u
Number of beads that Henry had less than Fabian at first
= 27 u - 25 u
= 2 u
2 u = 22
1 u = 22 ÷ 2 = 11
Number of beads that Henry had at first
= 25 u
= 25 x 11
= 275
Answer(s): 275
