Nick and Elijah gave away the same number of beads. Nick gave away
34 of his beads while Elijah gave
59 of his beads away. Given that Nick had 21 beads less than Elijah at first, how many beads did Nick have at first?
| |
Nick |
Elijah |
| Before |
4x5 =
20 u |
9x3 =
27 u |
| Change |
- 3x5 =
- 15 u |
- 5x3 =
- 15 u |
| After |
1x5 =
5 u |
4x3 =
12 u |
The number of beads that Nick and Elijah gave away is the same. Make the number of beads that Nick and Elijah gave away the same. LCM of 3 and 5 is 15.
Number of beads that Nick had at first = 20 u
Number of beads that Elijah had at first = 27 u
Number of beads that Nick had less than Elijah at first
= 27 u - 20 u
= 7 u
7 u = 21
1 u = 21 ÷ 7 = 3
Number of beads that Nick had at first
= 20 u
= 20 x 3
= 60
Answer(s): 60
