Jack and Paul gave away the same number of stickers. Jack gave away
35 of his stickers while Paul gave
59 of his stickers away. Given that Jack had 14 stickers less than Paul at first, how many stickers did Jack have at first?
|
Jack |
Paul |
Before |
5x5 = 25 u |
9x3 = 27 u |
Change |
- 3x5 = - 15 u |
- 5x3 = - 15 u |
After |
2x5 = 10 u |
4x3 = 12 u |
The number of stickers that Jack and Paul gave away is the same. Make the number of stickers that Jack and Paul gave away the same. LCM of 3 and 5 is 15.
Number of stickers that Jack had at first = 25 u
Number of stickers that Paul had at first = 27 u
Number of stickers that Jack had less than Paul at first
= 27 u - 25 u
= 2 u
2 u = 14
1 u = 14 ÷ 2 = 7
Number of stickers that Jack had at first
= 25 u
= 25 x 7
= 175
Answer(s): 175