Fred and Brandon gave away the same number of marbles. Fred gave away
35 of his marbles while Brandon gave
49 of his marbles away. Given that Fred had 21 marbles less than Brandon at first, how many marbles did Fred have at first?
| |
Fred |
Brandon |
| Before |
5x4 =
20 u |
9x3 =
27 u |
| Change |
- 3x4 =
- 12 u |
- 4x3 =
- 12 u |
| After |
2x4 =
8 u |
5x3 =
15 u |
The number of marbles that Fred and Brandon gave away is the same. Make the number of marbles that Fred and Brandon gave away the same. LCM of 3 and 4 is 12.
Number of marbles that Fred had at first = 20 u
Number of marbles that Brandon had at first = 27 u
Number of marbles that Fred had less than Brandon at first
= 27 u - 20 u
= 7 u
7 u = 21
1 u = 21 ÷ 7 = 3
Number of marbles that Fred had at first
= 20 u
= 20 x 3
= 60
Answer(s): 60
