Xavier and Dylan gave away the same number of marbles. Xavier gave away ⁶₁₁ of his marbles while Dylan gave ⁴₉ of his marbles away. Given that Xavier had 20 marbles less than Dylan at first, how many marbles did Xavier have at first?

	Xavier	Dylan
Before	11x2 = 22 u	9x3 = 27 u
Change	- 6x2 = - 12 u	- 4x3 = - 12 u
After	5x2 = 10 u	5x3 = 15 u

The number of marbles that Xavier and Dylan gave away is the same.  Make the number of marbles that Xavier and Dylan gave away the same. LCM of 6 and 4 is 12.

Number of marbles that Xavier had at first = 22 u
Number of marbles that Dylan had at first = 27 u

Number of marbles that Xavier had less than Dylan at first
= 27 u - 22 u
= 5 u

5 u = 20

1 u = 20 ÷ 5 = 4

Number of marbles that Xavier had at first
= 22 u
= 22 x 4
= 88

Answer(s): 88