Ahmad and Cody gave away the same number of beads. Ahmad gave away
35 of his beads while Cody gave
49 of his beads away. Given that Ahmad had 21 beads less than Cody at first, how many beads did Ahmad have at first?
| |
Ahmad |
Cody |
| Before |
5x4 =
20 u |
9x3 =
27 u |
| Change |
- 3x4 =
- 12 u |
- 4x3 =
- 12 u |
| After |
2x4 =
8 u |
5x3 =
15 u |
The number of beads that Ahmad and Cody gave away is the same. Make the number of beads that Ahmad and Cody gave away the same. LCM of 3 and 4 is 12.
Number of beads that Ahmad had at first = 20 u
Number of beads that Cody had at first = 27 u
Number of beads that Ahmad had less than Cody at first
= 27 u - 20 u
= 7 u
7 u = 21
1 u = 21 ÷ 7 = 3
Number of beads that Ahmad had at first
= 20 u
= 20 x 3
= 60
Answer(s): 60
