Ryan and Seth gave away the same number of coins. Ryan gave away
34 of his coins while Seth gave
49 of his coins away. Given that Ryan had 22 coins less than Seth at first, how many coins did Ryan have at first?
| |
Ryan |
Seth |
| Before |
4x4 =
16 u |
9x3 =
27 u |
| Change |
- 3x4 =
- 12 u |
- 4x3 =
- 12 u |
| After |
1x4 =
4 u |
5x3 =
15 u |
The number of coins that Ryan and Seth gave away is the same. Make the number of coins that Ryan and Seth gave away the same. LCM of 3 and 4 is 12.
Number of coins that Ryan had at first = 16 u
Number of coins that Seth had at first = 27 u
Number of coins that Ryan had less than Seth at first
= 27 u - 16 u
= 11 u
11 u = 22
1 u = 22 ÷ 11 = 2
Number of coins that Ryan had at first
= 16 u
= 16 x 2
= 32
Answer(s): 32
