Lee and Ben gave away the same number of beads. Lee gave away
34 of his beads while Ben gave
59 of his beads away. Given that Lee had 21 beads less than Ben at first, how many beads did Lee have at first?
| |
Lee |
Ben |
| Before |
4x5 =
20 u |
9x3 =
27 u |
| Change |
- 3x5 =
- 15 u |
- 5x3 =
- 15 u |
| After |
1x5 =
5 u |
4x3 =
12 u |
The number of beads that Lee and Ben gave away is the same. Make the number of beads that Lee and Ben gave away the same. LCM of 3 and 5 is 15.
Number of beads that Lee had at first = 20 u
Number of beads that Ben had at first = 27 u
Number of beads that Lee had less than Ben at first
= 27 u - 20 u
= 7 u
7 u = 21
1 u = 21 ÷ 7 = 3
Number of beads that Lee had at first
= 20 u
= 20 x 3
= 60
Answer(s): 60
