Eric and Lee gave away the same number of erasers. Eric gave away
35 of his erasers while Lee gave
49 of his erasers away. Given that Eric had 14 erasers less than Lee at first, how many erasers did Eric have at first?
|
Eric |
Lee |
Before |
5x4 = 20 u |
9x3 = 27 u |
Change |
- 3x4 = - 12 u |
- 4x3 = - 12 u |
After |
2x4 = 8 u |
5x3 = 15 u |
The number of erasers that Eric and Lee gave away is the same. Make the number of erasers that Eric and Lee gave away the same. LCM of 3 and 4 is 12.
Number of erasers that Eric had at first = 20 u
Number of erasers that Lee had at first = 27 u
Number of erasers that Eric had less than Lee at first
= 27 u - 20 u
= 7 u
7 u = 14
1 u = 14 ÷ 7 = 2
Number of erasers that Eric had at first
= 20 u
= 20 x 2
= 40
Answer(s): 40