Pierre and Lee gave away the same number of buttons. Pierre gave away
34 of his buttons while Lee gave
49 of his buttons away. Given that Pierre had 22 buttons less than Lee at first, how many buttons did Pierre have at first?
| |
Pierre |
Lee |
| Before |
4x4 =
16 u |
9x3 =
27 u |
| Change |
- 3x4 =
- 12 u |
- 4x3 =
- 12 u |
| After |
1x4 =
4 u |
5x3 =
15 u |
The number of buttons that Pierre and Lee gave away is the same. Make the number of buttons that Pierre and Lee gave away the same. LCM of 3 and 4 is 12.
Number of buttons that Pierre had at first = 16 u
Number of buttons that Lee had at first = 27 u
Number of buttons that Pierre had less than Lee at first
= 27 u - 16 u
= 11 u
11 u = 22
1 u = 22 ÷ 11 = 2
Number of buttons that Pierre had at first
= 16 u
= 16 x 2
= 32
Answer(s): 32
