Eric and Brandon gave away the same number of stamps. Eric gave away
34 of his stamps while Brandon gave
59 of his stamps away. Given that Eric had 21 stamps less than Brandon at first, how many stamps did Eric have at first?
| |
Eric |
Brandon |
| Before |
4x5 =
20 u |
9x3 =
27 u |
| Change |
- 3x5 =
- 15 u |
- 5x3 =
- 15 u |
| After |
1x5 =
5 u |
4x3 =
12 u |
The number of stamps that Eric and Brandon gave away is the same. Make the number of stamps that Eric and Brandon gave away the same. LCM of 3 and 5 is 15.
Number of stamps that Eric had at first = 20 u
Number of stamps that Brandon had at first = 27 u
Number of stamps that Eric had less than Brandon at first
= 27 u - 20 u
= 7 u
7 u = 21
1 u = 21 ÷ 7 = 3
Number of stamps that Eric had at first
= 20 u
= 20 x 3
= 60
Answer(s): 60
