Nick and Riordan gave away the same number of pens. Nick gave away
611 of his pens while Riordan gave
49 of his pens away. Given that Nick had 15 pens less than Riordan at first, how many pens did Nick have at first?
| |
Nick |
Riordan |
| Before |
11x2 =
22 u |
9x3 =
27 u |
| Change |
- 6x2 =
- 12 u |
- 4x3 =
- 12 u |
| After |
5x2 =
10 u |
5x3 =
15 u |
The number of pens that Nick and Riordan gave away is the same. Make the number of pens that Nick and Riordan gave away the same. LCM of 6 and 4 is 12.
Number of pens that Nick had at first = 22 u
Number of pens that Riordan had at first = 27 u
Number of pens that Nick had less than Riordan at first
= 27 u - 22 u
= 5 u
5 u = 15
1 u = 15 ÷ 5 = 3
Number of pens that Nick had at first
= 22 u
= 22 x 3
= 66
Answer(s): 66
