Luis and Valen gave away the same number of coins. Luis gave away
35 of his coins while Valen gave
59 of his coins away. Given that Luis had 10 coins less than Valen at first, how many coins did Luis have at first?
|
Luis |
Valen |
Before |
5x5 = 25 u |
9x3 = 27 u |
Change |
- 3x5 = - 15 u |
- 5x3 = - 15 u |
After |
2x5 = 10 u |
4x3 = 12 u |
The number of coins that Luis and Valen gave away is the same. Make the number of coins that Luis and Valen gave away the same. LCM of 3 and 5 is 15.
Number of coins that Luis had at first = 25 u
Number of coins that Valen had at first = 27 u
Number of coins that Luis had less than Valen at first
= 27 u - 25 u
= 2 u
2 u = 10
1 u = 10 ÷ 2 = 5
Number of coins that Luis had at first
= 25 u
= 25 x 5
= 125
Answer(s): 125