Bryan and Michael gave away the same number of marbles. Bryan gave away
34 of his marbles while Michael gave
49 of his marbles away. Given that Bryan had 22 marbles less than Michael at first, how many marbles did Bryan have at first?
|
Bryan |
Michael |
Before |
4x4 = 16 u |
9x3 = 27 u |
Change |
- 3x4 = - 12 u |
- 4x3 = - 12 u |
After |
1x4 = 4 u |
5x3 = 15 u |
The number of marbles that Bryan and Michael gave away is the same. Make the number of marbles that Bryan and Michael gave away the same. LCM of 3 and 4 is 12.
Number of marbles that Bryan had at first = 16 u
Number of marbles that Michael had at first = 27 u
Number of marbles that Bryan had less than Michael at first
= 27 u - 16 u
= 11 u
11 u = 22
1 u = 22 ÷ 11 = 2
Number of marbles that Bryan had at first
= 16 u
= 16 x 2
= 32
Answer(s): 32