Paul and Jenson gave away the same number of coins. Paul gave away
35 of his coins while Jenson gave
49 of his coins away. Given that Paul had 21 coins less than Jenson at first, how many coins did Paul have at first?
| |
Paul |
Jenson |
| Before |
5x4 =
20 u |
9x3 =
27 u |
| Change |
- 3x4 =
- 12 u |
- 4x3 =
- 12 u |
| After |
2x4 =
8 u |
5x3 =
15 u |
The number of coins that Paul and Jenson gave away is the same. Make the number of coins that Paul and Jenson gave away the same. LCM of 3 and 4 is 12.
Number of coins that Paul had at first = 20 u
Number of coins that Jenson had at first = 27 u
Number of coins that Paul had less than Jenson at first
= 27 u - 20 u
= 7 u
7 u = 21
1 u = 21 ÷ 7 = 3
Number of coins that Paul had at first
= 20 u
= 20 x 3
= 60
Answer(s): 60
