Rael and Michael gave away the same number of coins. Rael gave away
34 of his coins while Michael gave
59 of his coins away. Given that Rael had 14 coins less than Michael at first, how many coins did Rael have at first?
| |
Rael |
Michael |
| Before |
4x5 =
20 u |
9x3 =
27 u |
| Change |
- 3x5 =
- 15 u |
- 5x3 =
- 15 u |
| After |
1x5 =
5 u |
4x3 =
12 u |
The number of coins that Rael and Michael gave away is the same. Make the number of coins that Rael and Michael gave away the same. LCM of 3 and 5 is 15.
Number of coins that Rael had at first = 20 u
Number of coins that Michael had at first = 27 u
Number of coins that Rael had less than Michael at first
= 27 u - 20 u
= 7 u
7 u = 14
1 u = 14 ÷ 7 = 2
Number of coins that Rael had at first
= 20 u
= 20 x 2
= 40
Answer(s): 40
