Peter and Daniel gave away the same number of cards. Peter gave away
34 of his cards while Daniel gave
49 of his cards away. Given that Peter had 22 cards less than Daniel at first, how many cards did Peter have at first?
| |
Peter |
Daniel |
| Before |
4x4 =
16 u |
9x3 =
27 u |
| Change |
- 3x4 =
- 12 u |
- 4x3 =
- 12 u |
| After |
1x4 =
4 u |
5x3 =
15 u |
The number of cards that Peter and Daniel gave away is the same. Make the number of cards that Peter and Daniel gave away the same. LCM of 3 and 4 is 12.
Number of cards that Peter had at first = 16 u
Number of cards that Daniel had at first = 27 u
Number of cards that Peter had less than Daniel at first
= 27 u - 16 u
= 11 u
11 u = 22
1 u = 22 ÷ 11 = 2
Number of cards that Peter had at first
= 16 u
= 16 x 2
= 32
Answer(s): 32
