Charlie and Mark gave away the same number of beads. Charlie gave away
34 of his beads while Mark gave
59 of his beads away. Given that Charlie had 21 beads less than Mark at first, how many beads did Charlie have at first?
| |
Charlie |
Mark |
| Before |
4x5 =
20 u |
9x3 =
27 u |
| Change |
- 3x5 =
- 15 u |
- 5x3 =
- 15 u |
| After |
1x5 =
5 u |
4x3 =
12 u |
The number of beads that Charlie and Mark gave away is the same. Make the number of beads that Charlie and Mark gave away the same. LCM of 3 and 5 is 15.
Number of beads that Charlie had at first = 20 u
Number of beads that Mark had at first = 27 u
Number of beads that Charlie had less than Mark at first
= 27 u - 20 u
= 7 u
7 u = 21
1 u = 21 ÷ 7 = 3
Number of beads that Charlie had at first
= 20 u
= 20 x 3
= 60
Answer(s): 60
