Irene had 138 more pens than Hilda. After Hilda gave away
15 of her pens, Irene had twice as many pens as Hilda. How many pens did Hilda have at first?
| |
Irene |
Hilda |
Comparing Irene
and Hilda at first |
138 more |
|
| Before |
8 u |
5 u |
| Change |
|
- 1 u |
| After |
|
4 u |
Comparing Irene
and Hilda in the end |
2x4 =
8 u |
1x4 =
4 u |
The number of pens that Irene had at first and in the end remains unchanged. Make the number of pens that Irene had the same. LCM of 8 and 2 is 8.
Number of pens that Irene had more than Hilda at first
= 8 u - 5 u
= 3 u
3 u = 138
1 u = 138 ÷ 3 = 46
Number of pens that Hilda had at first
= 5 u
= 5 x 46
= 230
Answer(s): 230
