Xandra had 88 more coins than Jane. After Jane gave away
14 of her coins, Xandra had twice as many coins as Jane. How many coins did Jane have at first?
| |
Xandra |
Jane |
Comparing Xandra
and Jane at first |
88 more |
|
| Before |
6 u |
4 u |
| Change |
|
- 1 u |
| After |
|
3 u |
Comparing Xandra
and Jane in the end |
2x3 =
6 u |
1x3 =
3 u |
The number of coins that Xandra had at first and in the end remains unchanged. Make the number of coins that Xandra had the same. LCM of 6 and 2 is 6.
Number of coins that Xandra had more than Jane at first
= 6 u - 4 u
= 2 u
2 u = 88
1 u = 88 ÷ 2 = 44
Number of coins that Jane had at first
= 4 u
= 4 x 44
= 176
Answer(s): 176
