Gem had 80 more coins than Xandra. After Xandra gave away
14 of her coins, Gem had thrice as many coins as Xandra. How many coins did Xandra have at first?
| |
Gem |
Xandra |
Comparing Gem
and Xandra at first |
80 more |
|
| Before |
9 u |
4 u |
| Change |
|
- 1 u |
| After |
|
3 u |
Comparing Gem
and Xandra in the end |
3x3 =
9 u |
1x3 =
3 u |
The number of coins that Gem had at first and in the end remains unchanged. Make the number of coins that Gem had the same. LCM of 9 and 3 is 9.
Number of coins that Gem had more than Xandra at first
= 9 u - 4 u
= 5 u
5 u = 80
1 u = 80 ÷ 5 = 16
Number of coins that Xandra had at first
= 4 u
= 4 x 16
= 64
Answer(s): 64
