Xavier has
411 as many pens as Will. They have a total of 300 pens. How many pens must Will give to Xavier so that they will have the same number of pens?
| |
Xavier |
Will |
Total |
| Before |
4 u |
11 u |
15 u |
| Change |
+ ? |
- ? |
|
| After |
150 |
150 |
300 |
Total number of pens
= 4 u + 11 u
= 15 u
15 u = 300
1 u = 300 ÷ 15 = 20
Number of pens that each of them has in the end
= 300 ÷ 2
= 150
Number of pens that Xavier has
= 4 u
= 4 x 20
= 80
Number of pens that Will must give Xavier
= 150 - 80
= 70
Answer(s): 70
