George has
27 as many coins as Cole. They have a total of 288 coins. How many coins must Cole give to George so that they will have the same number of coins?
|
George |
Cole |
Total |
Before |
2 u |
7 u |
9 u |
Change |
+ ? |
- ? |
|
After |
144 |
144 |
288 |
Total number of coins
= 2 u + 7 u
= 9 u
9 u = 288
1 u = 288 ÷ 9 = 32
Number of coins that each of them has in the end
= 288 ÷ 2
= 144
Number of coins that George has
= 2 u
= 2 x 32
= 64
Number of coins that Cole must give George
= 144 - 64
= 80
Answer(s): 80