Xavier has
34 as many pens as Luke. They have a total of 280 pens. How many pens must Luke give to Xavier so that they will have the same number of pens?
|
Xavier |
Luke |
Total |
Before |
3 u |
4 u |
7 u |
Change |
+ ? |
- ? |
|
After |
140 |
140 |
280 |
Total number of pens
= 3 u + 4 u
= 7 u
7 u = 280
1 u = 280 ÷ 7 = 40
Number of pens that each of them has in the end
= 280 ÷ 2
= 140
Number of pens that Xavier has
= 3 u
= 3 x 40
= 120
Number of pens that Luke must give Xavier
= 140 - 120
= 20
Answer(s): 20