Gabriel has
35 as many erasers as Howard. They have a total of 280 erasers. How many erasers must Howard give to Gabriel so that they will have the same number of erasers?
| |
Gabriel |
Howard |
Total |
| Before |
3 u |
5 u |
8 u |
| Change |
+ ? |
- ? |
|
| After |
140 |
140 |
280 |
Total number of erasers
= 3 u + 5 u
= 8 u
8 u = 280
1 u = 280 ÷ 8 = 35
Number of erasers that each of them has in the end
= 280 ÷ 2
= 140
Number of erasers that Gabriel has
= 3 u
= 3 x 35
= 105
Number of erasers that Howard must give Gabriel
= 140 - 105
= 35
Answer(s): 35
