Howard has
59 as many beads as Daniel. They have a total of 280 beads. How many beads must Daniel give to Howard so that they will have the same number of beads?
| |
Howard |
Daniel |
Total |
| Before |
5 u |
9 u |
14 u |
| Change |
+ ? |
- ? |
|
| After |
140 |
140 |
280 |
Total number of beads
= 5 u + 9 u
= 14 u
14 u = 280
1 u = 280 ÷ 14 = 20
Number of beads that each of them has in the end
= 280 ÷ 2
= 140
Number of beads that Howard has
= 5 u
= 5 x 20
= 100
Number of beads that Daniel must give Howard
= 140 - 100
= 40
Answer(s): 40
