Seth has
38 as many coins as Mark. They have a total of 286 coins. How many coins must Mark give to Seth so that they will have the same number of coins?
|
Seth |
Mark |
Total |
Before |
3 u |
8 u |
11 u |
Change |
+ ? |
- ? |
|
After |
143 |
143 |
286 |
Total number of coins
= 3 u + 8 u
= 11 u
11 u = 286
1 u = 286 ÷ 11 = 26
Number of coins that each of them has in the end
= 286 ÷ 2
= 143
Number of coins that Seth has
= 3 u
= 3 x 26
= 78
Number of coins that Mark must give Seth
= 143 - 78
= 65
Answer(s): 65