Fanny was 8 years old last year. She was 22 years younger than Tina.
- How old will her Tina be 8 years later?
- In how many years' time will Fanny's age be 13 of Tina's age?
| |
Fanny |
Tina |
Difference |
| Before (Last year) |
8 |
30 |
22 |
| Change 1 |
+ 1 |
+ 1 |
|
| After 1 (Now) |
9 |
31 |
22 |
| Change 2 |
+ 8 |
+ 8 |
|
| After 2 (8 years later) |
|
? |
22 |
(a)
Tina's age this year
= 8 + 22
= 30
Tina's age this year
= 30 + 1
= 31
Tina's age in 8 years' time
= 31 + 8
= 39
| |
Fanny |
Tina |
Difference |
| Before |
9 |
31 |
22 |
| Change |
+ ? |
+ ? |
|
| After |
1 u |
3 u |
2 u |
(b)
The difference in the age between Fanny and Tina at first and in the end remains unchanged.
Difference in the age between Fanny and Tina
= 3 u - 1 u
= 2 u
2 u = 22
1 u = 22 ÷ 2 = 11
Number of years' time that Fanny's age be
13 of Tina's age
= 11 - 9
= 2
Answer(s): (a) 39; (b) 2
