Tina was 5 years old last year. She was 22 years younger than Hazel.
- How old will her Hazel be 7 years later?
- In how many years' time will Tina's age be 13 of Hazel's age?
| |
Tina |
Hazel |
Difference |
| Before (Last year) |
5 |
27 |
22 |
| Change 1 |
+ 1 |
+ 1 |
|
| After 1 (Now) |
6 |
28 |
22 |
| Change 2 |
+ 7 |
+ 7 |
|
| After 2 (7 years later) |
|
? |
22 |
(a)
Hazel's age this year
= 5 + 22
= 27
Hazel's age this year
= 27 + 1
= 28
Hazel's age in 7 years' time
= 28 + 7
= 35
| |
Tina |
Hazel |
Difference |
| Before |
6 |
28 |
22 |
| Change |
+ ? |
+ ? |
|
| After |
1 u |
3 u |
2 u |
(b)
The difference in the age between Tina and Hazel at first and in the end remains unchanged.
Difference in the age between Tina and Hazel
= 3 u - 1 u
= 2 u
2 u = 22
1 u = 22 ÷ 2 = 11
Number of years' time that Tina's age be
13 of Hazel's age
= 11 - 6
= 5
Answer(s): (a) 35; (b) 5
