Yen was 5 years old last year. She was 27 years younger than Xandra.
- How old will her Xandra be 4 years later?
- In how many years' time will Yen's age be 14 of Xandra's age?
| |
Yen |
Xandra |
Difference |
| Before (Last year) |
5 |
32 |
27 |
| Change 1 |
+ 1 |
+ 1 |
|
| After 1 (Now) |
6 |
33 |
27 |
| Change 2 |
+ 4 |
+ 4 |
|
| After 2 (4 years later) |
|
? |
27 |
(a)
Xandra's age this year
= 5 + 27
= 32
Xandra's age this year
= 32 + 1
= 33
Xandra's age in 4 years' time
= 33 + 4
= 37
| |
Yen |
Xandra |
Difference |
| Before |
6 |
33 |
27 |
| Change |
+ ? |
+ ? |
|
| After |
1 u |
4 u |
3 u |
(b)
The difference in the age between Yen and Xandra at first and in the end remains unchanged.
Difference in the age between Yen and Xandra
= 4 u - 1 u
= 3 u
3 u = 27
1 u = 27 ÷ 3 = 9
Number of years' time that Yen's age be
14 of Xandra's age
= 9 - 6
= 3
Answer(s): (a) 37; (b) 3
