Fanny was 5 years old last year. She was 26 years younger than Jaslyn.
- How old will her Jaslyn be 3 years later?
- In how many years' time will Fanny's age be 13 of Jaslyn's age?
| |
Fanny |
Jaslyn |
Difference |
| Before (Last year) |
5 |
31 |
26 |
| Change 1 |
+ 1 |
+ 1 |
|
| After 1 (Now) |
6 |
32 |
26 |
| Change 2 |
+ 3 |
+ 3 |
|
| After 2 (3 years later) |
|
? |
26 |
(a)
Jaslyn's age this year
= 5 + 26
= 31
Jaslyn's age this year
= 31 + 1
= 32
Jaslyn's age in 3 years' time
= 32 + 3
= 35
| |
Fanny |
Jaslyn |
Difference |
| Before |
6 |
32 |
26 |
| Change |
+ ? |
+ ? |
|
| After |
1 u |
3 u |
2 u |
(b)
The difference in the age between Fanny and Jaslyn at first and in the end remains unchanged.
Difference in the age between Fanny and Jaslyn
= 3 u - 1 u
= 2 u
2 u = 26
1 u = 26 ÷ 2 = 13
Number of years' time that Fanny's age be
13 of Jaslyn's age
= 13 - 6
= 7
Answer(s): (a) 35; (b) 7
