Shannon was 8 years old last year. She was 28 years younger than Joelle.
- How old will her Joelle be 4 years later?
- In how many years' time will Shannon's age be 13 of Joelle's age?
| |
Shannon |
Joelle |
Difference |
| Before (Last year) |
8 |
36 |
28 |
| Change 1 |
+ 1 |
+ 1 |
|
| After 1 (Now) |
9 |
37 |
28 |
| Change 2 |
+ 4 |
+ 4 |
|
| After 2 (4 years later) |
|
? |
28 |
(a)
Joelle's age this year
= 8 + 28
= 36
Joelle's age this year
= 36 + 1
= 37
Joelle's age in 4 years' time
= 37 + 4
= 41
| |
Shannon |
Joelle |
Difference |
| Before |
9 |
37 |
28 |
| Change |
+ ? |
+ ? |
|
| After |
1 u |
3 u |
2 u |
(b)
The difference in the age between Shannon and Joelle at first and in the end remains unchanged.
Difference in the age between Shannon and Joelle
= 3 u - 1 u
= 2 u
2 u = 28
1 u = 28 ÷ 2 = 14
Number of years' time that Shannon's age be
13 of Joelle's age
= 14 - 9
= 5
Answer(s): (a) 41; (b) 5
