Ahmad and Pierre had $151 at first. Ahmad spent $78 while Pierre spent $16 less than him. The amount Pierre had left was
38 of the amount Ahmad had left. How much did Ahmad have at first?
| |
Ahmad |
Pierre |
Total |
| Before |
3 u + 78 |
8 u + 62 |
151 |
| Change |
- 78 |
- 62 |
|
| After |
3 u |
8 u |
|
Amount that Pierre had spent
= 78 - 16
= $62
Total amount that Ahmad and Pierre had at first
= 3 u + 78 + 8 u + 62
= 11 u + 140
11 u + 140 = 151
11 u = 151 - 140
11 u = 11
1 u = 11 ÷ 11 = 1
Amount that Ahmad had at first
= 8 u + 78
= 8 x 1 + 78
= 8 + 78
= $86
Answer(s): $86
