Pierre and Riordan had $125 at first. Pierre spent $69 while Riordan spent $49 less than him. The amount Riordan had left was
45 of the amount Pierre had left. How much did Pierre have at first?
| |
Pierre |
Riordan |
Total |
| Before |
4 u + 69 |
5 u + 20 |
125 |
| Change |
- 69 |
- 20 |
|
| After |
4 u |
5 u |
|
Amount that Riordan had spent
= 69 - 49
= $20
Total amount that Pierre and Riordan had at first
= 4 u + 69 + 5 u + 20
= 9 u + 89
9 u + 89 = 125
9 u = 125 - 89
9 u = 36
1 u = 36 ÷ 9 = 4
Amount that Pierre had at first
= 5 u + 69
= 5 x 4 + 69
= 20 + 69
= $89
Answer(s): $89
