Pierre and Jenson had $162 at first. Pierre spent $50 while Jenson spent $18 less than him. The amount Jenson had left was
35 of the amount Pierre had left. How much did Pierre have at first?
| |
Pierre |
Jenson |
Total |
| Before |
3 u + 50 |
5 u + 32 |
162 |
| Change |
- 50 |
- 32 |
|
| After |
3 u |
5 u |
|
Amount that Jenson had spent
= 50 - 18
= $32
Total amount that Pierre and Jenson had at first
= 3 u + 50 + 5 u + 32
= 8 u + 82
8 u + 82 = 162
8 u = 162 - 82
8 u = 80
1 u = 80 ÷ 8 = 10
Amount that Pierre had at first
= 5 u + 50
= 5 x 10 + 50
= 50 + 50
= $100
Answer(s): $100
