At a farm, there were
79 as many cows and geese. The farmer added another 30 cows but sold away 41 geese. In the end, there were 9 geese more than cows. How many cows and geese were there altogether in the end?
|
Cows |
Geese |
Before |
7 u |
9 u |
Change |
+ 30 |
- 41 |
After |
7 u + 30 |
9 u - 41 |
If the farmer had another 9 cows in the end, the number of cows and (chickens) would be the same.
9 u - 41 = 7 u + 30 + 9
9 u - 7 u = 39 + 41
2 u = 80
1 u = 80 ÷ 2 = 40
Number of geese and cows in the end
= 7 u + 30 + 9 u - 41
= 7 u + 9 u + 30 - 41
= 16 u - 11
= 16 x 40 - 11
= 629
Answer(s): 629